# 2481 vs 1028

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This one is a puzzle with no end solution i aim at.
Considering there were a series of shocking coincidences that happaned to me in MD, i am thinking that there might be something in this too since there is a visual similarity to it. it might be nothing also.
When you look for somehting, you will find it, have no doubt about that. You tell me what you found and i will decide on my own if the discovery is a stretched answer or its indeed an interesting coincidence to consider.

What could possibly be the relation (math, geometry, logic, history, anything) between the following numbers. They may be seen as a number or a series of individual numbers in that order, at most shifted, but not mixed. finding a mathematical way to shift them both to the same result using same formula is also an interesting find. (except the obvious zero multiplication and such)

[b]2481 vs 1028[/b]

the first is the balance model i am researching in md and the second is my id totally random selected at that time. It happend i made 1028 days with id 1028 at 28 years (accounts start at 1000 so mine is nr 28). There are other things that made me look a bit at potential funny coincidences between numbers that i run into in general. Lets see if any can find something about this particular pair.

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If you divide the variables by each other (ignoring the zero because you cannot divide by zero) you get the same answer.

2481:
2/4 = .5/8 = .0625/1 = .0625

1028:
1/2 = .5/8 = .0625

Not sure if that counts =)

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2481 - 1028 = 1453
This the last year of the Middle Ages and the end of the Hundred Years' War.

I see it as a sign of darkness and light.

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See my next post below :-)

Cutler

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[quote name='cutler121' timestamp='1295795826' post='77919']
Here is a series of numbers with Murs two numbers as the second and eleventh elements. I will just list the first few in the series and leave the "rules" as an exercise so I don't ruin it.1248 2481 <-- Murs first number48168163 163232646412128225655121 1024 <-- Murs second number2048409681921638327665531310Cutler
[/quote]

arnt murs Numbers 2481 and 1028? Thusly The series doesnt include 1028 as you have highlighted 1024

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[quote name='Chewett' timestamp='1295797723' post='77920']
arnt murs Numbers 2481 and 1028? Thusly The series doesnt include 1028 as you have highlighted 1024
[/quote]

Lol

OOps I read the number incorrectly.

Feel free to keep neg repping me though.

Lol

Cutler

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[quote ]2481 - 1028 = 1453
This the last year of the Middle Ages and the end of the Hundred Years' War. [/quote]

I would disagree that 1453 it the end of the Middle Ages since the Renaissance started mid-1300s in Florence, or very early 1400s if you want to count when the printing press was invented as being the start.

Unless, of course, you are referring to 1453 as being the year that the Byzantium Empire ended when Constantinople fell.

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Ok,

So this is just about as random as you can get, but it does provide a nice mathematical formula for the (correct) two numbers Mur provided and the first number in the sequence also just happens to be the exact number of days in a year which is interesting.

The sequence I define as Mur#(N) is

Mur#(N) = (6-N)*( N^5 + (N+1)^4 + (N+2)^3 + (N+3)^2 + (N+4)^1 + (N+1)*(2*N)^2 + (N-1)^(N+1))

The first four Mur numbers are :

Mur#(1) = 365 <--- Days in a year
Mur#(2) = 1028 <--- Murs first number
Mur#(3) = 2481 <--- Murs second number
Mur#(4) = 4970 <--- any significance?

Cutler

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[quote name='Brulant' timestamp='1295803986' post='77926']
I would disagree that 1453 it the end of the Middle Ages since the Renaissance started mid-1300s in Florence, or very early 1400s if you want to count when the printing press was invented as being the start.

Unless, of course, you are referring to 1453 as being the year that the Byzantium Empire ended when Constantinople fell.
[/quote]

Yes, it refers to the end of Byzantine Empire. I was just referring to http://en.wikipedia.org/wiki/1453 where you can find more details.

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since one of the numbers is not a serial representation (as in onethousandthewntyeight) but a parallel one like two.four.eight.one i am tempted to see what the difference between them actually is if size is left aside.

this might be too intuitevely for a math mind but math was never my strong point so...
here is what i got so far, maybe one of you can find better on same concept

2481
1028

shifted becomes

1248
1028

difference remains 24 to 02, with 24 being the result of a shift. Shifted back after the comparison, it makes 4 related to 0 somehow.
This might have been obvious from the initial numbers but if placed in any other order the numbers would have been impossible to compare other than just taking out the numbers that differ.

0 in md (1028 is related to md)
4 in rl (2481 is a balance model in rl)

An other possible meaning could be 2 becomes 4 while 0 becomes 2, while this is a mathematical nonesense it might be a logical deduction somehow.

Comparing the numbers in other numeric bases especially 2, or xor'ing them, might show other things

Again, this will probably lead nowhere, but its interesting to see

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You're opening a can of worms for that, but try with this:

1-2-4-8 (2^X)

0-1-2-8 (you notice 2^2= 4 is missing, instead you have a 0)

1-0-2-8 (1 to 0, to 2, and then..?)

It's not about the way you order it, it's about the way you leap. (Maybe you get what I mean)

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as for the 2481 vs 1028 problem, I have this:

in binary code,they are writen:
2481: 1001.1011.0001
1028: 0100.0000.0100
Notice that 2481 have 4 "1`s" more then 1028, the same difference in their digits =]

also, 1248 vs 1028 is:

1248: 0100.1110.0000
1028: 0100.0000.0100
1248: 4.14.0
1028: 4.0.4
there are four "4`s" also the different digit =]

beware of the evil hidden fours >:]

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My intuitive decomposition of those numbers is:

2481: 2^5 * 3 * 5^2 + (3^2)^2
1028: 2^5 * 2^5 + 2^2

Vaguely similar.

2481 = 3 * 1028 - 3^2 * (2 * 2^5 + 3) , but here I'm kinda forcing a relation to the above.

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